at first I want to tell the problem of checkpoint 04
The challenge is this. write a function that accepts an integer from 1 through 10000 and return the integer square root of that number. That sounds easy but there are some catches:
1 if the number is less than 1 or greater than 10000 you should throw an"out of bounds" error
2 you should only consider integer square roots don't worry about the square root of 3 being 1.732 for example.
3 if you can't find the square root, throw a " no root" error
The anwser is that
`import Foundation
func findSquareroot ( for myNumber:Int ) throws -> Int { // guard 与 if差不多 不够if还有其他选择 而guard只有确定 判定为否时
guard myNumber >= 1 && myNumber <= 10000 else { throw SquareRootError.outOfBounds } for i in 1...myNumber { if myNumber == i*i {
return i } } throw SquareRootErrors.noRoot } let myNumber = 101
do{ let result = try findSquareroot(for: myNumber)
print("The square root of (myNumber) is (result)")
} catch SquareRootErrors.outOfBounds{
print( "The nunber you provided isnot with in the accepted range") }catch SqaureRootErrors.noRoot { print(" The number of your choice has no square root")
}`
and then we should talk How to deal with Error
such as How to Handle errors in functions
`do {
try throwingFunction01()
nonThrowingFunction1()
try throwingFunction02()
nonThrowingFunction2()
try throwingFunction3()
}catch
{
}`
