function binary(num) {
if (isNaN(num)) return;
let arr = [];
while (num > 0) {
//只有商为0的时候才是计算到最后了
if (num % 2 == 0) {
arr.push(0);
} else {
arr.push(1);
}
num = parseInt(num / 2);
}
//因为二进制取值的是是从后向前取的,所以要翻转数组
return arr.reverse().join("");
}
从网上看到的另一种方法
function dec2bin(th) {
dec = th;
bin = "";
while (dec > 0) {
if (dec % 2 != 0) {
bin = "1" + bin;
} else {
bin = "0" + bin;
}
dec = parseInt(dec / 2);
}
return bin;
}
```