python – PyQt – 如果UI已经运行,如何检测和关闭它？ - 代码日志我从Maya内部启动UI.如果UI尚未

我从Maya内部启动UI.如果UI尚未关闭,再次运行UI将完全冻结Maya(错误“事件循环已在运行”)

在重新运行脚本之前手动关闭UI将阻止它冻结.但我想这不太实际.

有没有办法检测我正在尝试运行的UI是否已经存在？可能的力量关闭它？

最佳答案给出了here,有几个相当简单的C解决方案.

我已将其中一个移植到PyQt,并在下面提供了一个示例脚本.原始C解决方案已分为两类,因为可能不需要消息传递工具.

更新：

改进了脚本,以便它使用新式信号并与python2和python3一起使用.

# only needed for python2
import sip
sip.setapi('QString', 2)

from PyQt4 import QtGui, QtCore, QtNetwork

class SingleApplication(QtGui.QApplication):
    messageAvailable = QtCore.pyqtSignal(object)

    def __init__(self, argv, key):
        QtGui.QApplication.__init__(self, argv)
        self._memory = QtCore.QSharedMemory(self)
        self._memory.setKey(key)
        if self._memory.attach():
            self._running = True
        else:
            self._running = False
            if not self._memory.create(1):
                raise RuntimeError(self._memory.errorString())

    def isRunning(self):
        return self._running

class SingleApplicationWithMessaging(SingleApplication):
    def __init__(self, argv, key):
        SingleApplication.__init__(self, argv, key)
        self._key = key
        self._timeout = 1000
        self._server = QtNetwork.QLocalServer(self)
        if not self.isRunning():
            self._server.newConnection.connect(self.handleMessage)
            self._server.listen(self._key)

    def handleMessage(self):
        socket = self._server.nextPendingConnection()
        if socket.waitForReadyRead(self._timeout):
            self.messageAvailable.emit(
                socket.readAll().data().decode('utf-8'))
            socket.disconnectFromServer()
        else:
            QtCore.qDebug(socket.errorString())

    def sendMessage(self, message):
        if self.isRunning():
            socket = QtNetwork.QLocalSocket(self)
            socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
            if not socket.waitForConnected(self._timeout):
                print(socket.errorString())
                return False
            if not isinstance(message, bytes):
                message = message.encode('utf-8')
            socket.write(message)
            if not socket.waitForBytesWritten(self._timeout):
                print(socket.errorString())
                return False
            socket.disconnectFromServer()
            return True
        return False

class Window(QtGui.QWidget):
    def __init__(self):
        QtGui.QWidget.__init__(self)
        self.edit = QtGui.QLineEdit(self)
        self.edit.setMinimumWidth(300)
        layout = QtGui.QVBoxLayout(self)
        layout.addWidget(self.edit)

    def handleMessage(self, message):
        self.edit.setText(message)

if __name__ == '__main__':

    import sys

    key = 'app-name'

    # send commandline args as message
    if len(sys.argv) > 1:
        app = SingleApplicationWithMessaging(sys.argv, key)
        if app.isRunning():
            print('app is already running')
            app.sendMessage(' '.join(sys.argv[1:]))
            sys.exit(1)
    else:
        app = SingleApplication(sys.argv, key)
        if app.isRunning():
            print('app is already running')
            sys.exit(1)

    window = Window()
    app.messageAvailable.connect(window.handleMessage)
    window.show()

    sys.exit(app.exec_())

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